They say it is better medicine to get something wrong and learn then to get 10 problems right.

My brother says I am overdosing!

]]>Bob

]]>Glad that you got it.

You're welcome!

Thanks bob and gAr, I finally got it!

]]>2*d = c

g = 2*h

(c+d)+2*b+3*a = e + 3*f + 4*(g+h)Using first 2 equations, 3rd one is

3*d + 2*b + 3*a = e + 2*f + 12*h

Yes, that's 3f in the last one, sorry about that!

Now you would get it, bobbym.

Bob

]]>Thanks for the drawing, I think I got it. It looks too simple to make a mistake on but...

Hi gAr;

I still can not genenrate your answers.

]]>see picture

edit

3d+2b+3a=e+2f+12h

I think you meant 3f

Bob

]]>Yes, what did I do wrong?

]]>Is it displayed in the right order? a,b,c... ?

]]>None of my solutions are correct. I think I got messed up. One more question though, when I solve gAr's equations I get:

This does not coincide with gAr's post #12.

Post #26 is what I used.

]]>That's not my idea, that's how torques are to be calculated !

The masses of the sub balances are added.

So in 1*12, 1 is the distance from the fulcrum and 12 is the weight in the sub balance: 8+4

Similarly the 4*9 : 4 is the distance from fulcrum, 9 is the weight 6+3

Hi Bob,

Just saw your post.

Yes, the "law of moments". I keep on forgetting the names!

Only just got to this. I think the rule

A weight that is placed two sections away from the middle will become twice as heavy as a weight that is placed one section away.

is just the 'law of moments'. I'm with gAr on this one, and I agree with both answers. (#12)

bobbym: Post another of your solutions please and I'll check it again the law.

Bob

]]>You have totally different idea than I had. Yours works. One question for the two on the bottom, I see 1* 12, how do you get 4 * 9?

]]>But you said you got 184 solutions?

And in #14 you wrote

3*9 + 2*5 + 2*8 = 1*7 + 3* 2 + 1*4 + 3* 6 + 6 * 3

It should be

3*9 + 2*5 + 1*12 = 1*7 + 3*2 + 4*9