The smaller number to meet this criteria is 5x12 = 60, then 120, then 180 etc.

Moreover, x should be a multiple of 7, thus (x+1)mod7 = 1, thus 120-1 = 119, 238 etc.

The number also has to be <150, so it is 119.]]>

Welcome to the forum. This should clear up the confusion.

Everyone did answer 119 ( see post #2,3 and 5).

The higher number (2519) was for the second problem (post #8) which does not have the <120 restriction.

]]>The question clearly says less than 150 eggs

So why do we have answers by the xxxxxdigits?

It's simply 119 eggs!

]]>2519 that is what I am getting also.

]]>I think the answer would be 2519.

]]>If he were to say:

"When counted in twos, 1 remains,

When counted in threes, 2 remain,

When counted in fours, 3 remain,

When counted in fives, 4 remain,

When counted in sixes, 5 remain,

When counted in sevens, 6 remain,...

so on till

When counted in elevens, none remain"

Will the least answer be 30239?

Could anyone verify if this would be the least answer...thanks..

]]>Each mutiplication does not effect the solution set. But you multiply until the number is congruent to 1 for the modulo. This has the effect of solving for the variable.

]]>why did you multiply with 3*3*...?

]]>Both your ans are correct.

]]>yup i did this problem except it wasn't bout eggs.

]]>

I got

Bob

]]>"When counted in twos, 1 remains,

When counted in threes, 2 remain,

When counted in fours, 3 remain,

When counted in fives, 4 remain,

When counted in sixes, 5 remain,

When counted in sevens, none remain...

I had less than 150 eggs."

How many eggs did he have?