just for reference reasons, here is the graph of logx :

as we can see, logx will go to ∞ when x gets larger and larger. but ∞ is not a number and consequently we cannot evaluate log(∞). however, if we know what happens to x as it approaches ∞, we can easily compute the limit of logt. here is how:

lim(x->∞ ) logx

as x -> ∞, we know t = x -> (∞) = ∞

lim(t->∞ )logt = ∞

hope this helps!!!

]]>]]>I would like to know, if the limit of a logarithmic funcation, lim(log(ax/bx+c)), when x --> infinity, is log(lim(ax/bx+c)) when x--> infinty, due to the logarithmic function behavior.

Thanks!

Núria

Thanks!

Núria