A place were we could store images we post here!

You could create a small quota for each user, lets say, 15 or 20 mb, wich is more than enought for gif/jp*g images.

]]>opposite sides are parallel, and equal; opposite angles are equal, and the diagonals (lines inside that intersect) bisect each other.

When you know the length of the diagonals, half of them would be the sides of a traingle they form with one of the sides of the parallelogram.

Use the theorems that (i) when two lines intersect each other, the vertically opposite angles are equal and (ii) sum of the total angles is equal to 360 degrees. This way, all the angles can be known.

Now, use the Cosine Theorem

a² = b² + c² - 2bcCosA

(where A, B, C are three angles of a traingle and a,b,c are the three sides opposite to angles A,B,C respectively)

for knowing the third side of the triangle, which forms a side of the parallelogram. Following this method, the adjacent side too can be found! Since opposite sides of a parallelogram are equal, we know all the four sides!

I know this reply is long, and may not be of much help; that's because some Mathematical problems are difficult to explain without a diagram!

]]>I do have an experimental image gallery, but I disabled it after the hacking attack for fear that was how they got in (example: they may have found a way to uploaded a program that they could then run). When the image gallery is stable and secure, then I will try to get it integrated with the forum so people can upload images here. That'd be nice!

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