a * b = { (a-1)² + b, if a > b
{ b(b-1) + a, otherwise
Here's how to start "counting" using this system.
1*1 = 1
2*1 = 2
1*2 = 3
2*2 = 4
3*1 = 5
3*2 = 6
1*3 = 7
2*3 = 8
3*3 = 9
4*1 = 10
...
n=1 has only one solution for a and b
1*1=1
]]>Thanks for the help=)
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