Changing the B+D=13 To:
B + C = 13: A=3,B=5,C=8,D=6
A + D = 13: A=5,B=3,C=6,D=8
A + C = 13: No Solution!
Given that A,B,C and D are whole numbers.Such that A+B=8,B+D=11,B+D=13 and C+D=14
find the value of A,B,C,D ?
Although it looks like a typo, the problem is perfectly acceptable. It just has no solution.
Systems that simplify down to false (for example, equations such as 1 = 0). Such systems have no points of intersection and no solutions.
B + D = 11
B + D = 13
Subtract the above equations from each other.
0 = - 2 False
]]>Given that A,B,C and D are whole numbers.Such that A+B=8,B+D=11,B+D=13 and C+D=14
find the value of A,B,C,D ?
in this question B+D had two values.
Is this question right ?
]]>Male:Female :: 6:5, so you want to multiply by 5/11 instead.
]]>A)6/11*138=76 females
is it right ?
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