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]]>Okay, and good luck again.

]]>Edit:Typo.

]]>Yes, had the answer written down already. He does it slightly different in the link I found. Using Calculus on it is overkill.

What is your textbook?

]]>Let me try to comprehend what you did there. http://i46.tinypic.com/2l9gsvl.png

Was that correct analysis?

I forgot that the angle at the bottom is the same as the second angle I pointed (or you did) out in the middle of the diagram.

Oh boy, thanks a lot once more Bobby.

Edit: Didn't see the link you posted. Interesting. And I guess he likely had the same question from the textbook as well.

]]>I formed the equation: Where y is the length of the ladder.

Set that equal to 0 and solve for theta

Plug it back into the original equation.

x = 479.1149 cm

This is straight from my notes, but I remember this problem. I google for it and come up with this.

http://ca.answers.yahoo.com/question/in … 608AAWEw2N

I have a numerical solution that is more interesting.

]]>A tool shed, 250 cm high and 100 cm deep, is built against a wall. Calculate the shortest ladder that can reach from the ground, over the shed, and to the wall behind.

Here's my attempt:

Letting y=the length of ladder: The length before the ladder touches the shed's top = 2.5/cos(v) and the other length = 1/cos(u).

y=2.5/cos(v) + 1/cos(u)

y'=2.5sin(v)/[cos(v)]^2 + sin(u)/[cos(u)]^2

I'm not sure where to go from there. I did this stuff so long ago, it's out of memory. Any hints?

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