You mean I got some of that right!!!!! I knew those Tarot cards worked.
Thanks man. I am glad you got it. I can do some stats and I like it. I am unusually good in stats, getting half of the questions right, provided it is a 2 choice per question test. I know what you would do without me, better! Bring it in and if I am around I will help. Don't worry about the soup.
Just let me say, thanks for saying those kind things, lately I have been feeling pretty unappreciated by some people.
]]>thanks for your help again this time! Dont know what I would do without you! I have it all written out now again (your explanation) and understand it perfectly. Are you any good on Stats? I am OK a while but might have a few questions in June. The soup and the wine was nice. But all gone by the end of the 80 mile cycle yesterday morning! I suppose one cant really share cyber soup! However! Thanks again!
Mickeen
]]>Enjoyed working on c), thanks for posting it. Save me some soup.
]]>mickeen
]]>For a) this came to me while doing c)
http://www.sosmath.com/trig/Trig5/trig5/trig5.html
The sum to product formulas:
Just say u = 2A and v = 2B
And you get:
]]>(b) If A + B + C = 180 degrees,
show that Sin (A + B) = Sin C
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For C)
Sin 2A + Sin 2B _ Sin 2C = 4CosACosBSinC.
I going to assume you meant:
remember sin(C) = sin(A+B)
See the result I gave you in post #6, Use it right here.
Done!
]]>(a) Express Sin2A + Sin2B as a product in Sine and Cosine.
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a) First thing that comes to mind is:
b) If A + B + C = 180 then A + B = 180 - C and
sin( 180 - c ) = sin(180° )cos(c) - cos(180° )sin(c)
= sin(c)
For c)
(c) Hence show that Sin 2A + Sin 2B _ Sin 2C = 4CosACosBSinC.
What does the underscore mean?
]]>(b) If A + B + C = 180 degrees,
show that Sin (A + B) = Sin C
(c) Hence show that Sin 2A + Sin 2B _ Sin 2C = 4CosACosBSinC.
Note: Cos(A + B) = - CosC
Can anyone plese help me on the last part of this question which has bothered me for some time now.
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