37 is eliminated because it's odd, not even (same as for 27).

Sorry, that's the second time I made the same stupid error. I have adjusted the post and thanks for spotting it.

]]>I wasn't able to eliminate 37 with my method

37 is eliminated because it's odd, not even (same as for 27).

Thanks for the additional work.

I think I like the algebraic approach best. Spreadsheet is good too...like getting a program to run successfully. And Goal Seek is nice - seeing the numbers spin around until the solution is found, and watching "WRONG!" change to "SOLVED!". Pardon my delight...my efforts don't always work out so well!

]]>Thanks for the additional work. I wasn't able to eliminate 37 with my method. It just isn't strong enough to get but 1 solution.

]]>Here are solution strategies like the ones I posted for Edna's age puzzle:

Excel spreadsheet image below (just change Ann's bogus age in C10 as per E10's instruction). Goal Seek aid included.

]]>Thanks for providing that!

]]>Basically it worked like this and I think it's just for this problem. The last clue that Rita was at one time 6 times as old as Ann gives these possibilities:

Age of Ann Age of Rita Difference in age now

1 6 5

2 12 10

3 18 15

4 24 20

5 30 25

6 36 30

7 42 35

What the chart says is that only when Ann was 1 to 7 could Rita have been 6 times older. Now if we say that A= Anns age now then Rita's age is one of these:

A+(A+5) =44 A = 19.5 impossible.

A+(A+10) =44 A = 17 and Ritas age is 27 (impossible 27 is odd))

A+(A+15) =44 A = 14.5 impossible

A+(A+20) =44 A = 12 Rita's is 32 Hooray!

A+(A+25) =44 A = 9.5 impossible

A+(A+30) =44 A = 7 Rita's is 37 (impossible 37 is odd)

A+(A+35) =44 A = 4.5 impossible

So only using 2 clues I can reduce this down to 2 answers. So this method is not as good as yours.

]]>You got it!

What method did you use?

I'm just starting to type out a method that basically follows the spreadsheet one, but expresses it differently. I'll post it soon.

]]>Absolutely right! The method I am using only yields 2 possible choices and I managed to pick the wrong one. Sorry to probe around like this but If I don't have the right answer this time I will have to scrap my entire idea. So please bear with me.

]]>

bobbym wrote:

Hi phrontister;

If I got this right then I have a different method.

Sorry, but that can't work because:

]]>

If I got this right then I have a different method.

]]>

Rita is twice as old as Ann will be when Rita is half as old as Ann will be when Ann is 3 times as old as Rita was when Rita was 6 times as old as Ann.

The sum of the ages of Rita and Ann is 44.

What is Rita's age?

]]>