For example √x² = x is is the same as saying (x²)^½ = x^(2/2) = x^1 = x

So, 4√x³y x 4√xy² = x^(3/4) × y^(1/4) × x^(1/4) × y^(2/4)

Combining terms: x^(4/4) × y^(3/4)

Simplifying: x × y^(3/4) = x 4√y³ (x times fourth root of y cubed)

]]>Multiply the terms: 4√((x^4)y³)

4√x^4=x, so taking x out of the 4th root gives x(4√y³)

Your answer should have the 4th root of y³ instead of the square root.

So, yes, minor typo error.

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You're right, it does work if there's a plus sign between 3/2(x-1) and √(2x²-7x-4). I checked the question and there's no plus sign, so I guess it could be a typo error.

I was given a typed up booklet just to familiarise and practise on, I hope there's no more other typos or I'll just get stressed up for doing wrong questions.

]]>3/2(x-1)+√(2x²-7x-4)

I wouldn't have any idea how to solve it if you hadn't already given us the answer though.

Squaring is easy, you can just follow a set of rules to get the answer every time.

Isn't it weird how the inverse can be so much more horrible?

I'm new here and need some help with this maths problem.

Here's a pic of the question and the answer and I've tried doing a method but my head can't get round this.

Any help appreciated.

Thanks in advance.

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