won't the ques be
26 - 63 = -1
]]>thank u ....
]]>2 even digits on the right they wanted which are 4 or 6 digits.
Then that leaves 3 ways because of 3 digits to pick from, either
3,4,5 or 3,5,6 if 4 was used. Then after that, there are only
2 digits left over to pick from for the leftmost digit because
there was just 3 left over before picking the middle one.
That's the gist of it anyway.
wat is this right ...left????
i really did'nt understand . pls explain again..
]]>Solution:- 1)
There are 4 digits 3,4,5 and 6
Number of 3 digit numbers = its not ^4P3 that 3 is below P =4× 3 ×2
= 242nd part of the question
boxes:- H T U
2ways 3 ways 2 ways 2)
how did they get 2 ways ,3 ways, 2 ways?
]]>How many 3-digit numbers can be formed by using the digits 3,4,5 and 6 without repetitions? How many of these are even?
Solution:- 1)
There are 4 digits 3,4,5 and 6
Number of 3 digit numbers =
2nd part of the question
boxes:- H T U
2ways 3 ways 2 ways 2)
Consider 3 -blank boxes
Step 1) First fill up the units place.This place can be filled by any one of the digits 4 or 6 in 2 ways.
Step2) After filling this place, three digits are left out. So the tens place can be filled in 3 ways.
Step3)Similiarly, the hundreds place can be filled in the remaining 2 digits in 2 ways.
By the fundamental principle,all the 3 places can be filled in 2× 3× 2 =12 ways