WELL done, mathsy, and I hope you are right, too!

(Regarding symbols, I don't think there is a special "-1" defined, but there *may* be some kludge to make a little "-")

]]>under. And the mechanical excercise is now solved, thank

to your algebraic consultancy. A big thanks to you!]]>

Start by extending the bottom of the triangle towards the red line to make a bigger, right-angled triangle. Then take away the triangle that contains the angle that you want, leaving you a smaller right-angled triangle. We know that the left side of this is 210m, because we are told that part of this is 120m and the rest of it is 90m, and we know that its bottom side is 70m, because looking at the measurements of 30 and 90 tell you that the hypotenuse goes up 3 times as much as it goes across.

Using trigonometry, we can work out that the angle next to your wanted angle is tan^-1(210/70), which is ∼71.6°. As angles on a straight line add up to 180°, the final step is to take 71.6° from 180° to give your answer: **∼108.4°.**

If you want the exact answer, it's 180- tan^-1(3).

I'm interested in your other problem too, but I'm a bit exhausted after doing this one so I'll do it later.

P.S. To MathsIsFun, can you add little -1 to the list of symbols?

]]>Hate having to sit by my self with this kind of lousy problems.

Actually this is a part of a quite simple mechanical problem, and

I'm almost 100 percent sure of that the way they mean, is to be

able to calculate that angle. But, it doesn't seem like that should

be a big problem. I mean, calculating that angle shouldn't be the

head task of the exercise. So, I hope that your answer is not too

advanced, even thought I will appreciate it equally much, my friend!

/Gustav]]>

for the best. Well, i have other problems too, but to get rid of one or

two of them would make my day!

Just check this link out, for the problem:

http://engman.bravehost.com/Jobb/algebra2.JPG

/Gustav

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