Cos2x+Cos3x=0
Cos2x=-Cos3x
Cos2x=Cos(pi-3x)
1)2x=3x-pi->x=pi->cosx=-1
2)2x=pi-3x->x=pi/5
looks like something is wrong with your equation...
You're right.
I'm actually rather stupid.
The factor should be (x+1), in which case x = -1 does work, as we can let x = cosθ (which we have to do anyway). Also,
Thanks
The point of the question was obviously to work in the trigonometric form, as the value of phi s.t
isn't obvious.]]>I've done the first part using induction. The polynomials I chose were:
However, the last part is a bit tricky.
I can't see how to write this in the form
though. I know that andCan anyone help? (Small hints preferred) Thanks.
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