Then for the equation.

using factorization. In the following manner.

Then the solutions are.

]]>6+/-1 5..

30+/- 1 7..

210 +/- 1 11..

2310 +/- 1 13..

equals primes......to a certain point above highest prime squared. e.g.>9,25,49,121 or 169 accordingly. And so on but the numbers get very big but you can do this up to infinity.

]]>Welcome to the forum.

thanks

]]>This is part of new way to find an alternative proof for Fermat's Last Theorem, I have stumbled at this part for power n=3.

]]>Has the form

year today(n)-(year today-1)

Say n is 10. The year now is 2014. Here is the formula:

2014(10)-2013 (results 18,127)

If the result is prime, it is a yearly prime.

***Case for odd years***

year today(n)-(year today-2)

Say n is 10. The year now is 2013. Here is the formula:

2013(10)-2011 (18,119)

18,119 is also a yearly prime.

***Canvassing of yearly primes***

Come, join me to discover yearly primes! If you have one, tell me in this topic. Happy searching!

]]>I still think of it as a concept. You can not do algebra on it like the Reals.

MIF wrote:

Just think "endless", or "boundless".

Any real number is not endless or boundless, so if you add 1 to it is is larger than before. Since infinity is endless, ∞+1 = ∞, ∞ + ∞ = ∞ etc.

There are systems as Shivam is pointing out where infinity may be defined differently.

]]>I think it was because of all the fun he was having when he started it.

]]>